Remark 5: Exactness of Sequences #
Statement #
For a graph G = (V, E) with a collection of cycles C (where each cycle c ∈ C is specified by its edge set, and each vertex of G that appears in c is incident to exactly two edges of c), the maps ∂₂ and ∂ satisfy the chain complex property ∂ ∘ ∂₂ = 0.
Similarly, δ₂ ∘ δ = 0 holds by transposition.
For a connected graph, ker(δ) = {0, 1} (constant functions), so the sequences are not short exact since ker(δ) ≠ 0.
If C generates the cycle space (im(∂₂) = ker(∂)), then ker(∂) = im(∂₂).
Main Results #
boundary_comp_secondBoundary_eq_zero: ∂ ∘ ∂₂ = 0 (chain complex property)secondCoboundary_comp_coboundary_eq_zero: δ₂ ∘ δ = 0 (by transposition)range_secondBoundary_le_ker_boundary: im(∂₂) ≤ ker(∂)range_coboundary_le_ker_secondCoboundary: im(δ) ≤ ker(δ₂)allOnes_mem_ker_coboundary: the all-ones vector is in ker(δ)ker_coboundary_connected: for connected G, ker(δ) = {0, 1}ker_coboundary_ne_bot: ker(δ) ≠ 0 (sequences are not short exact)
Chain Complex Property: ∂ ∘ ∂₂ = 0 #
Helper: if every cycle in the collection has the property that each vertex is incident to an even number of its edges, then the boundary of a single cycle indicator is zero.
∂₂(1_c) applied through ∂ gives zero for each cycle c.
Chain complex property: ∂ ∘ ∂₂ = 0, given that each cycle in the collection has the property that each vertex is incident to an even number of its edges.
im(∂₂) ≤ ker(∂).
Coboundary Chain Complex: δ₂ ∘ δ = 0 #
Coboundary chain complex property: δ₂ ∘ δ = 0. By transposition from ∂ ∘ ∂₂ = 0.
im(δ) ≤ ker(δ₂).
Kernel of the Coboundary Map #
The all-ones vector is in ker(δ).
Any constant function is in ker(δ).
f ∈ ker(δ) implies f(a) = f(b) for adjacent a, b.
f ∈ ker(δ) implies f is constant along walks.
f ∈ ker(δ) implies f is constant on reachable vertices.
For a connected graph, f ∈ ker(δ) implies f is a constant function.
For a connected graph, ker(δ) consists exactly of the constant functions {0, 1}.
ker(δ) ≠ 0: the sequences are not short exact.
Corollaries #
For any σ, ∂(∂₂ σ) = 0.
For any f, δ₂(δ f) = 0.